Breuken vermenigvuldigen en machtsverheffen
$breuk\times breuk=\Large\frac{teller\times teller}{noemer\times noemer}$
$
\Large\frac{1}{3} \times \frac{3}{4} = \frac{{1 \cdot 3}}{{3 \cdot 4}} = \frac{3}{{12}} = \frac{1}{4}
$
$\Large(\frac{teller}{noemer})^{n}$=$\Large\frac{teller^{n}}{noemer^{n}}$
$
\Large\left( {\frac{2}{3}} \right)^3 = \frac{{2^3 }}{{3^3 }} = \frac{8}{{27}}
$
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