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$y=2(x-4)^{2}+4$
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$y=-(x+3)^{2}-11$
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$y=-\frac{2}{3}(x+1\frac{1}{2})^{2}+2\frac{3}{4}$
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$y=x^{2}+3$
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$y=(x+7)^{2}$
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$\left( {4,4} \right)$
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$\left( {-3,-11} \right)$
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$\left( {-1\frac{1}{2},2\frac{3}{4}} \right)$
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$\left( {0,3} \right)$
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$\left( {-7,0} \right)$
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