|
Oplossing week 14 |
$
\eqalign{
& \Delta ABS:O = \frac{1}
{2} \cdot z \cdot \frac{2}
{3}z = \frac{1}
{3}z^2 \cr
& \Delta BPS:O = \frac{1}
{2} \cdot \frac{1}
{2}z \cdot \frac{1}
{3}z = \frac{1}
{{12}}z^2 \cr
& ABPS = \frac{{\frac{1}
{3}z^2 + \frac{1}
{{12}}z^2 }}
{{z^2 }} = \frac{5}
{{12}} \cr}
$
$\eqalign{\frac{5}{12}}$-deel van het vierkant is gekleurd.
©2004-2024 Wiskundeleraar - login