$3^{x+1}=80$
$x+1=^3log(80)$
$x=-1+^3log(80)$ |
$5+2^{3x}=25$
$2^{3x}=20$
$3x=^2log(20)$
$x=\frac{1}{3}·^2log(20)$ |
$\eqalign{4-log(\frac{1}{x})=2}$
$\eqalign{-log(\frac{1}{x})=-2}$
$\eqalign{log(\frac{1}{x})=2}$
$\eqalign{\frac{1}{x}=100}$
$\eqalign{x=\frac{1}{100}}$ |
