uitgewerkt

$
\begin{array}{l}
a. \\
f(x) = (2x - 3){}^4 \\
f\,'(x) = 4\left( {2x - 3} \right)^3 \cdot 2 \\
f\,'(x) = 8\left( {2x - 3} \right)^3 \\
\end{array}
$
$
\eqalign{
& b. \cr
& g(x) = \sqrt {4x - 9} \cr
& g\,'(x) = \frac{1}
{{2\sqrt {4x - 9} }} \cdot 4 \cr
& g\,'(x) = \frac{2}
{{\sqrt {4x - 9} }} \cr}
$
$
\eqalign{
& c. \cr
& h(x) = \frac{2}
{{5x - 1}} \cr
& h(x) = 2 \cdot \left( {5x - 1} \right)^{ - 1} \cr
& h\,'(x) = 2 \cdot - 1 \cdot \left( {5x - 1} \right)^{ - 2} \cdot 5 \cr
& h\,'(x) = \frac{{ - 10}}
{{\left( {5x - 1} \right)^2 }} \cr}
$

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