![q11286img1.gif](/bestanden/q11286img1.gif)
$
\eqalign{
& \Delta ABS:O = \frac{1}
{2} \cdot z \cdot \frac{2}
{3}z = \frac{1}
{3}z^2 \cr
& \Delta BPS:O = \frac{1}
{2} \cdot \frac{1}
{2}z \cdot \frac{1}
{3}z = \frac{1}
{{12}}z^2 \cr
& ABPS = \frac{{\frac{1}
{3}z^2 + \frac{1}
{{12}}z^2 }}
{{z^2 }} = \frac{5}
{{12}} \cr}
$
$\eqalign{\frac{5}{12}}$-deel van het vierkant is gekleurd.
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