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Opgave 1
Opgave 2
Opgave 3
a.
3x2 $-$ 12 = 0
x2 $-$ 4 = 0
x2 = 4
x = $-\sqrt{4}$ of x=$\sqrt{4}$
x = $-$2 of x = 2
c.
3x2 + 12x + 12 = 0
x2 + 4x + 4 = 0
(x + 2)2 = 0
x + 2 = 0
x = $-$2
Opgave 3
b.
3x2 + 12x = 0
3x(x + 4) = 0
3x = 0 of x + 4 = 0
x = 0 of x = $-$4
d.
(4x - 1)($\frac{1}{2}$x + 6) = 0
4x - 1 = 0 of $\frac{1}{2}$x + 6 = 0
4x = 1 of $\frac{1}{2}$x = $-$6
x = $\frac{1}{4}$ of x = $-$12