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$ \eqalign{{3 \over {x - 1}} + {2 \over x} = {{3x} \over {x\left( {x - 1} \right)}} + {{2\left( {x - 1} \right)} \over {x(x - 1)}} = {{3x + 2x - 2} \over {x(x - 1)}} = {{5x - 2} \over {x(x - 1)}}} $